Optimal. Leaf size=196 \[ \frac{a \sin (e+f x) \cos (e+f x) \cos ^2(e+f x)^{\frac{1}{2} (-n-1)} (d \cos (e+f x))^n F_1\left (\frac{1}{2};\frac{1}{2} (-n-1),1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )}-\frac{b \sin (e+f x) \cos ^2(e+f x)^{-n/2} (d \cos (e+f x))^n F_1\left (\frac{1}{2};-\frac{n}{2},1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )} \]
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Rubi [A] time = 0.365425, antiderivative size = 196, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {4264, 3869, 2823, 3189, 429} \[ \frac{a \sin (e+f x) \cos (e+f x) \cos ^2(e+f x)^{\frac{1}{2} (-n-1)} (d \cos (e+f x))^n F_1\left (\frac{1}{2};\frac{1}{2} (-n-1),1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )}-\frac{b \sin (e+f x) \cos ^2(e+f x)^{-n/2} (d \cos (e+f x))^n F_1\left (\frac{1}{2};-\frac{n}{2},1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )} \]
Antiderivative was successfully verified.
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Rule 4264
Rule 3869
Rule 2823
Rule 3189
Rule 429
Rubi steps
\begin{align*} \int \frac{(d \cos (e+f x))^n}{a+b \sec (e+f x)} \, dx &=\left ((d \cos (e+f x))^n (d \sec (e+f x))^n\right ) \int \frac{(d \sec (e+f x))^{-n}}{a+b \sec (e+f x)} \, dx\\ &=\left (\cos ^{-n}(e+f x) (d \cos (e+f x))^n\right ) \int \frac{\cos ^{1+n}(e+f x)}{b+a \cos (e+f x)} \, dx\\ &=-\left (\left (a \cos ^{-n}(e+f x) (d \cos (e+f x))^n\right ) \int \frac{\cos ^{2+n}(e+f x)}{b^2-a^2 \cos ^2(e+f x)} \, dx\right )+\left (b \cos ^{-n}(e+f x) (d \cos (e+f x))^n\right ) \int \frac{\cos ^{1+n}(e+f x)}{b^2-a^2 \cos ^2(e+f x)} \, dx\\ &=-\frac{\left (a \cos ^{2 \left (\frac{1}{2}+\frac{n}{2}\right )-n}(e+f x) (d \cos (e+f x))^n \cos ^2(e+f x)^{-\frac{1}{2}-\frac{n}{2}}\right ) \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^{\frac{1+n}{2}}}{-a^2+b^2+a^2 x^2} \, dx,x,\sin (e+f x)\right )}{f}+\frac{\left (b (d \cos (e+f x))^n \cos ^2(e+f x)^{-n/2}\right ) \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^{n/2}}{-a^2+b^2+a^2 x^2} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{a F_1\left (\frac{1}{2};\frac{1}{2} (-1-n),1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) \cos (e+f x) (d \cos (e+f x))^n \cos ^2(e+f x)^{\frac{1}{2} (-1-n)} \sin (e+f x)}{\left (a^2-b^2\right ) f}-\frac{b F_1\left (\frac{1}{2};-\frac{n}{2},1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) (d \cos (e+f x))^n \cos ^2(e+f x)^{-n/2} \sin (e+f x)}{\left (a^2-b^2\right ) f}\\ \end{align*}
Mathematica [B] time = 25.6473, size = 5216, normalized size = 26.61 \[ \text{Result too large to show} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.782, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( d\cos \left ( fx+e \right ) \right ) ^{n}}{a+b\sec \left ( fx+e \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \cos \left (f x + e\right )\right )^{n}}{b \sec \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (d \cos \left (f x + e\right )\right )^{n}}{b \sec \left (f x + e\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \cos{\left (e + f x \right )}\right )^{n}}{a + b \sec{\left (e + f x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \cos \left (f x + e\right )\right )^{n}}{b \sec \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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